SIMO Retiree Blog

(David here.) In this post, I go through a surprisingly tricky functional equation that appeared on the 2018 edition of the IMO Revenge, a contest where the contestants made problems for their trainers. The problem (IMO Revenge 2018/4) Find all functions $f:\mathbb{Q}\rightarrow\mathbb{R}$ such that $$f(x)^2-f(y)^2=f(x+y)\cdot f(x-y)$$ for all $x,y\in \mathbb{Q}$. Fun fact - I was actually at that IMO as an observer! I had good memories of attempting the test, solving problem 3 and meeting the contestant-proposer (who later went on to propose an actual IMO Q3). Initial observations Clearly, $f(x) = x$ works. Furthermore, the equation is homogeneous in $f$ - if $f$ works then so must $cf$. It's also cheap to get that $f(0) = 0$ and $f(-x) = -f(x)$. This was roughly where I ran out of cheap things to find - I didn't manage to get any more special values or any standard properties (like injectivity or surjectivity). Some progress When you get stuck on a functional equati...

(This is Yan Sheng.) Last time we studied a family of inequalities involving absolute values on linear polynomials, and asked the question of how lazy we can be to prove inequalities of that form. This week, we will be applying the same approach to a different family: 3-variable homogeneous symmetric inequalities of low degree. A polynomial $P(x,y,z)$ in 3 variables is called homogeneous of degree $d$ if each of its terms is of degree $d$, and symmetric if $P(x,y,z)=P(x',y',z')$ for all permutations $x',y',z'$ of $x,y,z$. Inequalities involving homogeneous symmetric polynomials include the AM-GM inequality$$\left(\frac{x+y+z}3\right)^3\ge xyz,$$and the Schur inequality$$x^r(x-y)(x-z)+y^r(y-x)(y-z)+z^r(z-x)(z-y)\ge0$$for integers $r\ge0$. For the rest of this post, write $\mathcal P^+_d$ for the family of all homogeneous symmetric polynomials $P(x,y,z)$ of degree $d$ such that $P(x,y,z)\ge0$ holds for all $x,y,z\ge0$. Our Main Problem is to describe $\math...

(This is Yan Sheng.) What does it mean to "properly understand" some mathematical result? For me, I find it the most satisfying when I can answer the following two questions: What is the minimal set of special cases that I need to verify to prove it? How could I have come up with it myself? In this and the next blog post, I'll describe two different situations in olympiad inequalities that I've tried to understand better recently, by answering the two questions above. Theorem (Popoviciu 1965): Let $f:[a,b]\to\mathbb R$ be a convex function. Then for any $x,y,z\in[a,b]$, we have$$\begin{align*}&f(x)+f(y)+f(z)+3f\left(\frac{x+y+z}3\right)\\&\ge2\left(f\left(\frac{x+y}2\right)+\left(\frac{y+z}2\right)+\left(\frac{z+x}2\right)\right).\end{align*}$$ What an interesting statement! It's not immediately clear how to prove it with Jensen's inequality, and it makes me wonder what other similar inequalities hold for convex functions. Let's try provin...

This is Glen again. There's been a lack of regular olympiad content recently, and since no one posted this week I thought I'd attempt a problem and write about my thought process. There was some discussion recently on the retirees' Discord server about APMO, so I figured I'd look at the most recent iteration, and since I wanted to be able to solve the problem in a reasonable amount of time, I attempted Q1. Here's the problem: ( APMO 2024/1 ) Let $ABC$ be an acute triangle. Let $D$ be a point on side $AB$ and $E$ be a point on side $AC$ such that lines $BC$ and $DE$ are parallel. Let $X$ be an interior point of $BCED$. Suppose rays $DX$ and $EX$ meet side $BC$ at points $P$ and $Q$, respectively, such that both $P$ and $Q$ lie between $B$ and $C$. Suppose that the circumcircles of triangles $BQX$ and $CPX$ intersect at a point $Y \neq X$. Prove that the points $A, X$, and $Y$ are collinear. Preliminary thoughts First and foremost, here's a diagram: Sorry about th...